As shown in the figure below, two blocks are connected by a string of negligible

Question

As shown in the figure below, two blocks are connected by a string of negligible mass passing over a pulley of radius 0.110 m and moment of inertia I. The block on the frictionless incline is moving with a constant acceleration of magnitude a = 1.20 m/s2. (Let m1 = 17.0 kg, m2 = 22.5 kg, and = 37.0°.) From this information, we wish to find the moment of inertia of the pulley.

(a) What analysis model is appropriate for the blocks?

particle in equilibrium

particle under constant acceleration    

particle under constant speed

particle under constant angular acceleration

particle in simple harmonic motion

(b) What analysis model is appropriate for the pulley?

particle in equilibrium

particle under constant acceleration    

particle under constant speed

particle under constant angular acceleration

particle in simple harmonic motion

(c) From the analysis model in part (a), find the tension T1.
N

(d) From the analysis model in part (a), find the tension T2.
N

(e) From the analysis model in part (b), find a symbolic expression for the moment of inertia of the pulley in terms of the tensions T1 and T2, the pulley radius r, and the acceleration a.
I =

(f) Find the numerical value of the moment of inertia of the pulley.
kg · m2

Explanation / Answer

part a

partical under constsnt accelartion becuse there is constant force applied by tension in string and tension is constant so force is constant

F= ma

a= F/m so accelertion is also constant

part b

constant angular momentum

part c & D

by newton second law

T1 - m1gsin37 = ma

T1 -17*9.81sin37=17*1.20

T 1= 120.764 N

in second block

accelartion is also

m2g - T2 = m2a

T2 =m2g -m2a = 22.5(9.81-1.20) = 193.725 N

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