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Welcome to this IE. You may navigate to any page you've seen already using the IE tab on the right. Two coaxial cylindrical conductors are shown in perspective and cross-section above. The inner cylinder has radius a = 2 cm, length L = 10 m and carries a total charge of Q_inner = + 8 nC (1 nC = 10^-9C). The outer cylinder has an inner radius b = 6 cm, outer radius c = 7 cm, length L = 10 m and carries a total charge of Q_outer = -16 nC (1 nC = 10^-9C). What is E_x, the x-component of the electric field at point P which is located at the midpoint of the length of the cylinders at a distance r = 4 cm from the origin and makes an angle of 30 degree with the x-axis? E_x =

Explanation / Answer

Ans:- here using Gauss’s law

Note at p we only consider inner charge in Gauss’s law

So electric field for cylinder is

E = (1/20 )*(/r)

= (2/40)*(Q/L/r)

Ex = E cos 30 = 2*9*10^9*((8*10^-9/10)/0.04)*0.866

Ex = 311.77=312N/c

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