Write F = ma and equate with F = evB (the magnetic force) and a = (the centripet

Question

Write F = ma and equate with F = evB (the magnetic force) and a = (the centripetal acceleration) to describe the motion of the electron in a magnetic field B. Solve for the velocity v in terms of the other parameters. What do the quantities: m, e, v. and r refer to in the above equation? An electron is accelerated through a potential difference of V = 50 volts. How much kinetic energy K docs it gain? What is the electron speed v for Question 3 above? The electron is accelerated by a potential difference V (the plate voltage) as it travels from the cathode to the plate. In this process the electrostatic potential energy is converted into the kinetic energy of the electron.eV = 1/2 mv^2. Use the above result to solve for v (the electron velocity) and substitute in the result found in Question 1. Solve for e/m (the charge-to-mass ratio) in terms of the plate voltage F, the electron orbital radius r, and the other constants.

Explanation / Answer

ma=evb , so a=evB/m now a=v^2/r

so evb/m=v^2/r . so v=eBr/m.

b)m= mass , e= charge v= velocity, r= radius of circular motion.

c)kinetic energy due to potential difference= eV =1.6 * 10^-19 * 50 = 8 * 10^-18 eV.

d)if v is speed then 1/2mv^2=8*10^-18*1.6*10^-19 J . so v= 1.6 *10^-3 m/s

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.