Two long wires carrying currents are 0.1 m apart as shown below in the figure. T

Question

Two long wires carrying currents are 0.1 m apart as shown below in the figure. The left wire has a current IL= 5 A (into the page), while the right wire has a current IR= 11 A (out of the page).

Part A

What is the magnitude of the magnetic field created by the left wire at the midpoint, C?

Express your answer using three significant figures.

Part B

What is the direction of the magnetic field created by the left wire at the midpoint, C?

Please ChooseLEFT UP OUT OF THE PAGE RIGHT DOWN INTO THE PAGE

Part C

What is the magnitude of the magnetic field created by the right wire at the midpoint, C?

Part D

What is the direction of the magnetic field created by the right wire at the midpoint, C?

Please ChooseINTO THE PAGE RIGHT LEFT OUT OF THE PAGE DOWN UP

Part E

What is the magnitude of the TOTAL magnetic field at the midpoint, C?

Part F

What is the direction of the TOTAL magnetic field at the midpoint, C?

Please ChooseOUT OF THE PAGE LEFT RIGHT INTO THE PAGE UP DOWN

Part G

You now place a 15 cm long wire at the midpoint, C, which has a current of 10 A OUT of the page. What is the magnitude of the force on this third wire?

Part H

You now place a 15 cm long wire at the midpoint, C, which has a current of 10 A OUT of the page. What is the direction of the force on this third wire?

Please Choose

LEFT

INTO THE PAGE

UP

DOWN

OUT OF THE PAGE

RIGHT

Explanation / Answer

As currents flow in opposite directions, the magnetic field produced in between wires would be in the same direction and so they have to be added
a) Field due to 5 A at C =uoI/(2pi*r) = 2*10^-7*5/0.05 = 2*10^-5 T
b) The direction will be downward in the plane of the page
c) Field due to 11A at C = 2*10^-7*11/0.05 = 4.4*10^-5 T
d) direction is downward in the plane of the page
e) Hence total is 6.4*10^-5 T
f) Downward in the plane of the page
g) Force = B I L = 6.4*10*0.15*10^-5 = 9.6*10^-5 N
h) Direction is towards right

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