A block in the shape of a rectangular solid has a cross-sectional area of 3.41 c

Question

A block in the shape of a rectangular solid has a cross-sectional area of 3.41 cm2 across its width, a front-to-rear length of 19.6 cm, and a resistance of 1290 . The block's material contains 5.29 × 1022 conduction electrons/m3. A potential difference of 41.0 V is maintained between its front and rear faces. (a) What is the current in the block? (b) If the current density is uniform, what is its magnitude? What are (c) the drift velocity of the conduction electrons and (d) the magnitude of the electric field in the block?

Explanation / Answer

a)I = V/R = 41.0/1290 = 3.19*10^-2A

b) J = I/A = (3.19*10^-2)/(3.41*10^-4) = 90.55 A/m^2

c) vdrift = J/(n*q) = 90.55 /(5.29*10^22*1.60*10^-19) = 10.7*10^-3m/s

d) E = V/d = 41.0/0.196 = 209.2 V/m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.