iPad 9:06 PM 30%. ? Lab 30 Series and Parallel Circuits [Compatibility Mode) Hom
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iPad 9:06 PM 30%. ? Lab 30 Series and Parallel Circuits [Compatibility Mode) Home Insert Draw Layout Review View Arial Question? Use your findings to explain why strings of lights such as Christmas lights are better on a parallel circuit. 8. As an extension, of what we've done so far, how do you think the brightness of the three light bulbs in the circuit in Figure 2 would compare to each other? 9. Make the circuit and test your hypothesis. Were you correct Explain the result (Hint: if you haven't already, you may want to review your notes or text for analysis using equivalent circuits 10. Another way to probe this circuit is to check the voltage at tFigure 2. Series and parallel various points. (If you know the voltage drop across a component, you can use Ohm's law to find the current running through it). Measure the voltage Vab across the lone resistor in the circuit from Figure 2, and compare it to Vbc, the voltage drop across the pair of parallel resistors. combined. Question 3. Do the voltages Vab and Vrborate your observations of the brightness? Explain Question 4. Here is a more advanced experimental problem encountered in research labs. As you measured the voltage drop across the light bulb using a multimeter, you may have wondered why we ignored the current loop created by the multimeter leads. To be sure, a little bit of current does get diverted through the multimeter, but the meter is made to have a high intenal resistance to greatly restrict the current flowing through it. Let's do a little "back of the envelope calculation" to see how much current flows through the meter. To do this, we can treat it like a large resistor and follow the same methods we used for the parallel bulbs, except now the two resistance values are no longer identical. Show mathematically that if the meter's intermal resistance is 1000 times higher than the bulb's resistance, the current in the meter is 1000 times less than through the bulb. This proves why the meter has no discenible effect on the circuit.Explanation / Answer
2) In the case of series connection the voltage drops are different at different lights depending on the resistance it provides .And the light may get a low voltage which may damage it.
But in the case of parallel connection all the circuitry get the same voltage regardless of the resistance
8) The bulb which is connected across ab will glow more than the parallel bulbs,provided the bulbs have the same resistance
10) The current through it will be greater in the series bulb ,If the three lights are having same resistance ,then the combined resistance of the parallel bulbs will be less .the total current in the circuit will be given by v/R; where v is the voltage of the battery ,R is the total resistance .
Then the voltage across points ab and bc can be found by just multiplying the total current with each parts resistance .
The answer will show that vab is greater than vbc
But the current through the bulbs will be the corresponding voltage divided by corresponding resistance and this will be the same through the series and parallel resistors
But this current is shared by the two parallel bulbs
Thus the current through the parallel component will be half of that passing through the series component
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