Hi, using this data from my lab: what is the answer to the following question? T

Question

Hi, using this data from my lab:

what is the answer to the following question?

Thank you!!

Data Table 1 Angle of incline 30 degrees Mass of car Mc 0.4843 k Purpose: To determine work done against friction Suspend mass (g)d (m)f Car moving up incline Car m1 0.230 m2-0.185 f (N)Wf (J) 2.254 1.813 0.25 0.5635 0.453 down incline 0.25 Percent diffrence in W 19.50% Calculations (show work) Energy method calculations for Wf Data Table 2 Purpose: To determine work done against friction Angle of incline 45 degrees Mass of car Mc 0.4843 k Suspend mass (g)d (m)f Car moving up incline Car m1-0.372 m2-0.269 0.24 0.06 f (N)Wf (J) 3.6 3.6 0.874 0.158 down incline Percent diffrence in W 82%

Explanation / Answer

work done by the force of gravity on car

when it is up he incline is W = mg sin theta

up the incline the force of gravity component is mg sin theta

   Wg = 0.4843*9.8sin30*0.25 = -0.593 J
   wG = 0.4843*9.8sin60*0.25 = -1.02 J

DOWN THE INCLINE
   Wg = 0.4843*9.8sin30*0.25 = 0.593 J
   wG = 0.4843*9.8sin60*0.25 = 1.02 J

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