A baseball with a mass of 143 g is thrown horizontally with a speed of 41.1 m/s

Question

A baseball with a mass of 143 g is thrown horizontally with a speed of 41.1 m/s (92 mi/h) at a bat. The ball is in contact with the bat for 1.00 ms and then travels straight back at a speed of 45.9 m/s (103 mi/h). Determine the average force exerted on the ball by the bat. Neglect the weight of the ball (it is much smaller than the force of the bat) and choose the direction of the incoming ball to be positive. (Indicate the direction with the sign of your answer.) Can you write an expression for the average force exerted on the ball in terms of its change in momentum and the time the force acts? Can you write and expression for the change in momentum? Pay careful attention to the sign convention suggested in the statement of the problem. N

Explanation / Answer

consider definition of impulse

F*t = m*(v - u)

where v is final velocity, u is intial velocity

F is force t is time

so we work out average force

F = m*(v - u) / t

F = 0.143*(45.9 - (- 41.1))/0.001

(final velocity is in opposite direction to intial velocity so negative sign)

F = 12441 N

this is the force exerted on the BALL

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