Two cars collide at an intersection. Car A, with a mass of 2000 kg , is going fr
ID: 1438702 • Letter: T
Question
Two cars collide at an intersection. Car A, with a mass of 2000 kg , is going from west to east, while car B , of mass 1500 kg , is going from north to south at 13.0 m/s . As a result of this collision, the two cars become enmeshed and move as one afterward. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65.0 south of east from the point of impact.
How fast were the enmeshed cars moving just after the collision?
How fast was car A going just before the collision?
I cant seem to get the right answer..some people on here are using SIN and some are using TAN, and its the same directions, ie north west south east TY so much
Explanation / Answer
add the momentum vectors.
A has a momentum Pa = 2000*Va angle 0
B has a momentum Pb = 1500*13 angle -90 =19500 angle -90
R has momentum R = R angle -65
Ax = 2000*Va
Bx = 0
Rx = Rcos(-65)
Ay = 0
By = -19500
Ry = Rsin(-65)
summing x and y
2000*Va = Rcos(-65)
-19500 = Rsin(-65)
from the last, R = 21515
2000*Va = Rcos(-65)
2000*Va = 21515 cos(-65)
Va = 4.54m/s (b)
total mass is 3500 kg, so if total momentum (R) is 21515, then
Vr = 21515/3500 = 6.14 m/s (a)
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