In a high-energy physics experiment, a subnuclear particle moves in a circular a

Question

In a high-energy physics experiment, a subnuclear particle moves in a circular arc of 1.23E+0 m radius perpendicular to a magnetic field of 2.70E-2 T. The kinetic energy of the particle is determined to be 1.59E-14 J. Identify the particle from its mass. The masses are:

Assume that the particle is known to have a positive charge equal to the magnitude of the electron charge. Enter the name of the particle from the list given above. Answer is case sensitive!!.

Particle Mass positron 9.10×10-31kg muon 1.88×10-28kg pion 2.50×10-28kg kaon 8.84×10-28kg proton 1.67×10-27kg Dmeson 3.35×10-27kg

Explanation / Answer

here,

charge on particle , q = e = 1.6 * 10^-19 C

radius , r = 1.23 m

magnetic feild , B = 2.7 * 10^-2 T

r = m*v/q*B

m*v = 1.23 * 1.6 * 10^-19 * 0.027

m*v = 5.3 * 10^-21 ....(1)

and

KE = 0.5 * m * v^2 = 1.59 * 10^-14 J

m*v^2 = 3.18 * 10^-14 .....(2)

from (1) and (2)

v = 6 * 10^6 m/s

and m = 8.83 * 10^-28 kg

the particle is Kaon

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.