iPad 9:20 PM 66% com Risi www.utexa.. iPhone 4 L How Much probiotics MATLAB P Co
ID: 1439304 • Letter: I
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iPad 9:20 PM 66% com Risi www.utexa.. iPhone 4 L How Much probiotics MATLAB P Computer 3 Master.. Problem 14.43 MasteringPhysics 9 of 13 Problem 14.43 0 it is released from rest starting at an A simple pendulum is 0.42 rn long. At t angle of 15 Part A Ignoring friction, what will be the angular position of the pendulum at 0.35 s? Express your answer to two significant figures and include the appropriate units. 690.35 = | Value Units Submit Give U Part B Ignoring friction, what will be the angular position of the pendulum at t = 3.45 s? Express your answer to two significant figures and include the appropriate units. 345_ Value Units Submit Give UpExplanation / Answer
In this case the pendulum has motion described by
angle = 15 degrees cos( wt)
w is the angular frequency,
w = sqrt(g/L) = 4.83
L is the length and g is acc due to gravity
angle = 15 degrees cos( sqrt(g/L) t)
a) = 5.23deg
b) = 51.56deg
c) = 89.68deg
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