C https:// Assignment Responses/last? dep 13562875 Need Help? l Read it Talk to

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C https:// Assignment Responses/last? dep 13562875 Need Help? l Read it Talk to a Tutor 5. -10 points SerPSE8 28.P.015 My Notes Ask Your Teacher Two resistons connected in series have an equivalent resistance of 684.3 n. When they are connected in parallel, the equivalent resistance is 140.1 m. Find the resistance of each resistor. n (small resistance n (large resistance) Need Help? l Read it Talk to a Tutor 6. C+D -10 points SerPSE8 28.P.017. My Notes Ask Your Teacher Calculate the power delivered to each resistor in the circuit shown in the figure below. (Let R 5.00 n, R. 2.00 n, and V 21.0 V.) resistor R1 4.00-ohm resistor W resistor R W 1.00-ohm resistor W 1.00 4.000 Need Help? Read It Watch It Talk to a Tutor 7. -10 points SerPSE8 28.P.019 My Notes Ask Your Teacher

Explanation / Answer

5)

let R1 and R2 are the two resistors.

in series combination, Rs = R1 + R2

684.3 = R1 + R2 ----(1)

in parallel combination, Rp = R1*R2/(R1+R2)

140.1 = R1*R2/(R1+R2)

140.1 = R1*R2/684.3

R1*R2 = 140.1*684.3

R1*R2 = 95870.43 ----(2)

on solving equations 1 and 2

we get

R1 = 487.74 ohms

R2 = 196.56 ohms

6)

Net Resistance of the ckt, Rnet = 5 + 2*1/(2+1) + 4

= 9.67 ohms

current through R1, I1 = V/Rnet

= 21/9.67

= 2.17 A

power deliverd to R1, P1 = I1^2*R1 = 2.17^2*5 = 23.6 W

power deliverd to 4 ohms, P(4ohms) = I1^2*4 = 2.17^2*4 = 18.8 W

current through resistor R2, I2 = I1*1/(2+1)

= 2.17*1/(2+1)

= 0.723 A

power deliverd to R2 = I2^2*R2 = 0.723^2*2 = 1.05 W

current through 1 ohm = 2.17 - 0.723

= 1.45 A

power delivered to 1 ohm = 1.45^2*1

= 2.1 Watts

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