At the equator, the direction of Earth\'s magnetic field is horizontal and to th

Question

At the equator, the direction of Earth's magnetic field is horizontal and to the north, and the magnitude is 3.5 times 10^-5 T. What is the magnetic flux through a circular loop of radius 0.10 m, lying flat on the ground at the equator? What is the magnetic flux through the loop of radius 0.10 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop points northwest? At the equator, the direction of Earth's magnetic field is horizontal and to the north, and the magnitude is 3.5 times 10^-5 T. What is the magnetic flux through the loop of radius 0.10 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop is points due north? What is the magnetic flux through the loop of radius 0.10 m balanced on its edge on the ground at the equator, when the axis that runs perpendicular to the plane of the loop is points to the west?

Explanation / Answer

a)

phi = B A = (3.5 x 10^-5) * (3.1416*0.10^2) = 1.1 x 10^-6 Wb

b)

phi = B A cos(45) = (3.5 x 10^-5) * (3.1416*0.10^2) * cos(45)= 7.8 x 10^-7 Wb

c)

phi = B A cos(theta) = (3.5 x 10^-5) * (3.1416*0.10^2) * cos(0) = 1.2 x 10^-6 Wb

d)

phi = B A cos(theta) = (3.5 x 10^-5) * (3.1416*0.10^2) * cos(90) = 0 Wb

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