sapling learning 5.67-mm-high firefly sits on the axis of, and 11.1 cm in front

Question

sapling learning 5.67-mm-high firefly sits on the axis of, and 11.1 cm in front of the thin lens A, whose focal length Is 5.13 cm. Behind lens A there is another thin lens, lens B, with focal length 22.7 cm. The two lenses share a common axis and are 64.5 cm apart. Is the image of the firefly that lens B forms real or virtual? Virtual Real How far from lens B is this image located (expressed as a positive number? Number cm What is the height of this image (as a positive number)? Number m m Is this image upright or inverted with respect to the firefly? o Upright Inverted

Explanation / Answer

real image

u1 = object distance = 11.1 cm

f1 = 5.13 cm

use 1/f1 = 1/u1 + 1/v1

1/v1 = 1/f1 -1/u1

1/v1 = 1/5.13 - 1/11.1

v1 = 9.53 cm

new object distance for second lens = u2 = 64.5 - 9.53

u2 = 54.97 cm

f2 = 22.7 cm

1/f2 = 1/u2 + 1/v2

1/v2 = 1/22.7 - 1/54.97

v2 = final image = 38.66 cm

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magnification m = -v/u

m = -38.66/(11.1 )

m = -(-3.48 )

so image height Y' = 3.48 * 6.67 = 23.21 mm

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upright as m is +ve

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