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Problems: Collisions C fi https://www.flipitphysics.com/Course/ViewProblem?unitltemID-1503829&enrollmentID;=157832 Apps N Netflix g NEST Creighton FlipMPhysics e Chegg eadline: Openstax Facebook First National Ba P MasteringChem-Learning Catal t YouTube a Amazon D Etsy wR Word Reference P Dynamic Periodic whenTowork O% until Saturday, March Standard Exercise 7.21 7.68 Standard Exercise 7.42 Forensic scientists can determine the speed at which a rifle fires a bullet by shooting into a heavy block hanging by a wire. As the bullet embeds itself in the block, the block and embedded bullet swing up; the impact speed is determined from the maximum angle of the swing. Standard Exercise 7.45 1) Which would make the block swing higher, a 0.204 Ruger bullet of mass 2.14 g and muzzle speed 1290 m/s or a 7-mm Remington Magnum bullet of mass 9.71 g and muzzle speed 948 m/s? Assume the bullets enter the block right after leaving the muzzle of the rifle. Standard Exercise 7.49 ORuger bullet Remington Magnum bullet Submit Standard Exercise 7.51 Standard Exercise 7.52 2) Determine the mass of the block so that when hit by the bullet it will swing through a 60.0° angle. The block hangs from wire of length 1.35 m and negligible mass. (Express your answer to three significant figures.) Standard Exercise 7.54 kg Submit Standard Exercise 7.68 3) What is the speed of an 7.46-g bullet that causes the block to swing upward through a 30.0° angle? (Express your answer to three significant figures.) Standard Exercise 7.71 m/s Submit Standard Fxercice 8:48 PM 3/19/2016 I'm Cortana. Ask me anything ENG

Explanation / Answer

using law of conservation of energy

for m = 2.14g Ruger bullet

0.5*m*u^2 = (m+M)*g*h

h1 = (0.5*2.14*10^-3*1290^2)/(2.14*10^-3 + M)*9.81

For m = remington Magnum Bullet

h2 = (0.5*9.71*10^-3*948^2)/(9.71*10^-3 + M)*9.81

since h2>h1

then for Remington bullet

the swing will be more

2)
h = l*(1-cos(theta)) = 1.35*(1-cos(60)) = 0.675 m

then using

0.5*m*u^2 = (m+M)*g*h

(0.5*9.71*10^-3*948^2) = ((9.71*10^-3) + M)*9.81*0.675

4363.2 = M = 658.9 kg if it hits by a Remington Magnum Bullet

3) 0.5*m*u^2 = (m+M)*g*h

h = l*(1-cos(30)) = 1.35*(1-cos(30)) = 0.18 m

0.5*7.46*10^-3*u^2 = (7.46*10^-3 +658.9)*9.81*0.18

u = 558.5 m/s

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