Someone did these already and gave me all wrong answers. So don\'t try to copy i

Question

Someone did these already and gave me all wrong answers. So don't try to copy it. Thanks.

Answer:  

8. [5pt]
A capacitor consists of two conductive plates each with an area of 17.7 m2separated by a distance of 1.9 mm. What is the capacitance of this device?

Answer:  

9. [5pt]
For the capacitor in the previous problem, if there is a voltage 210.0 between the plates what will be the charge on each plate?

Answer:  

Answer:  

11. [5pt]
Which statements are true for two oppositely charged, isolated parallel plates: (C=capacitance, U=stored energy, +Q and -Q = charge on the plates). Note: Isolated plates can not lose their charge. (Give ALL correct answers, i.e., B, AC, BCD...)

A) When the distance is halved, Q stays the same.
B) Inserting a dielectric increases Q.
C) When the distance is doubled, U increases.
D) Inserting a dielectric decreases U.
E) Increasing the distance increases the Electric field.
F) When the distance is doubled, C increases.
G) Inserting a dielectric increases C.

Explanation / Answer

7.)

change in potential energy = work done

work done = 0 J

8.)C = E A/d

C = 8.85*10^-12 * 17.7/1.9*10^-3

C = 8.24*10^-8 F

9.) Q = CV

Q = 8.24*10^-8 * 210 = 1.73*10^-5 C

10.) C1 and C2 are connected in series

So net Capacitance C' = C1C2/(C1+C2)

C' = 7.5*7.6*10^-12 /(15.1*10^-6)

C' = 3.77*10^-6 F

C' and C3 are connected in parallel

net capaciatnce C = C'+C3 = 4.5*10^-6 + 3.77*10^-6 = 8.2 *10^-6 F

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