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In Figure 33-74, unpolarized light is sent into the system of three polarizing s

ID: 1440930 • Letter: I

Question

In Figure 33-74, unpolarized light is sent into the system of three polarizing sheets, where the polarizing directions of the first and third sheets are at angles 1 (counterclockwise) and 3 (clockwise) to the vertical. The middle polarizer is horizontal. What fraction of the initial light intensity emerges from the system? Express your answer in terms of 1 and 3.

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I3/I0 = ?

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Explanation / Answer

here

after passing through filter 1 = I1 = 0.5 * I0 because light initially unpolarized

after passing through filter 2 = I2 = I1 * cos^2( 90 - theta)

after passing through filter 3 = I3 = I2 * cos^2(90 + theta)

the fraction of initial light intensity is

I = ( 1/2) * cos^2( 90+ theta) * cos^2(90 - theta)

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