please answer all questions (a) How much charge is on the surface of an isolated

Question

please answer all questions

(a) How much charge is on the surface of an isolated spherical conductor that has a 11.9 cm radius and is charged to 2.10 kV? nC (b) What is the electrostatic potential energy of this conductor? (Assume the potential is zero far from the sphere.) If a conducting sphere is to be charged to a potential of 5000 what is the smallest possible radius of the sphere such that the electric field will not exceed the dielectric strength of air? mm A spherical conductor of radius R1 is charged to 26 kw. When it is connected by a long, very thin conducting wire to a second conducting sphere far away, its potential drops to 13 kV What is the radius of the second sphere as a multiple of R1?

Explanation / Answer

a) voltage, charge relation

V=Q/(4*3.14*8.85*10-12 R)

using V=2.1kv, R=0.119m

Q=2.76*10-8

b) Electrostatic energy relation

E=Q/(8*3.14*8.85*10-12 R)

E=1.78*10-5J

c) Dilectric strength of air is 3*106 V/m

electric field relation is

Electric field=Q/(4*3.14*8.85*10-12 R2)

3*106 V/m=5000V/R

R=1.6mm

d)

since the both sphere have same voltage 13kV each on both spheres than from relation

V=Q/(4*3.14*8.85*10-12 R)

both surfaces must have equal radius

R1=R2

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