number 8 7. When your car won\'t start in really cold weather, it is often becau

Question

number 8

7. When your car won't start in really cold weather, it is often because your battery has failed. A failing battery can sometimes be resuscitated by "jumping" it, as in the circuit diagram below. Determine the current in the starter and in the failing battery. With your solution, please re-draw the circuit diagram and label your loops and initial current direction arrows. Lon. 001 I 8. You wired up this circuit in lab and measured the current through the 2-n resistor to be 4 A. Unfortunately, the ammeter then broke before you could measure the current through the other three resistors. Use Kirchoff's Rules to determine the current in each of the other three resistors. WWW 22 Zov

Explanation / Answer

Here ,

for Using KCL at the nodes

I2 + I3 - I4 = 0 -----(1)

Using KVL in the left loop

70 - 2 * I2 - 4 I4 = 0

I2 + 2 * I4 = 35 ----(2)

Using KVL in the right loop

9 - 3 * I3 - 4 * I4 = 0

3 I3 + 4 I4 = 9 -----(3)

Using KVL in the outer loop

70 + I1 - 9 = 0 ----(4)

I1 = -61 A

the current in the 1 Ohm resistance is -61 A .

solving 1 ,2 ,3 ,4

I2 = 17.46 A

I3 = -8.7 A

I4 = 8.77 A

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