At this point you should realize (unless of course you didn\'t follow the direct

Question

At this point you should realize (unless of course you didn't follow the directions above) that the motion is circular. The force points towards the center of the circle. Assume in the following that the magnetic force in this case has a magnitude equal to Bqv. This is true for motion in a plane with B perpendicular to the plane. I he angle theta is therefore 90degree. Take the mass of the particle as m. Derive an equation for the radius of this motion in the space below. You do this by selling the magnetic force equal to the mass multiplied by the centripetal acceleration.

Explanation / Answer

Here ,

let the radius of motion is r

for the motion

centripetal force = magnetic force

m * v^2/r = B * v * q

solving for r

r = m * v/(B * q)

the radius of the motion is m * v/(B * q)

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