Let\'s look at a simple application of Faraday\'s law. In (Figure 1), the magnet
ID: 1441903 • Letter: L
Question
Let's look at a simple application of Faraday's law. In (Figure 1), the magnetic field in the region between the poles of the electromagnet is uniform at any tome but is increasing at the rate of 0.020T/s. The area of the conducting loop in the field is 120 cm^2, and the total circuit resistance, including the meter, is 5.0 ohm. Find the magnitudes of the induced emf and the induced current in the circuit. So the unit of deltapi_B/delta t is the volt, as is required. Also, recall that the unit of magnetic flux is 1 T. m^2 = 1 Wb, so 1 V = 1 Wb/s. Suppose we change the apparatus so that magnetic field increases at a rate of 0.19 T/s, the area of the conducting loop in the field is 0.025 m^2., and the total circuit resistance is 9.0 ohm. Find the magnetic of the induced emf. Express your answer in volts to two significant figures. Find the magnetic of the induced current in the circuit.Explanation / Answer
Here ,
dB/dt = 0.020 T/s
A = 120 cm^2
A = 1.20 *10^-2 m^2
R = 5 Ohm
induced emf = A * dB/dt
induced emf = 0.020 * 120 *10^-2
induced emf = 0.024 V
induced current = induced emf /R
induced current = 0.024/5 = 4.8 *10^-3 A
----------------------------------
part A)
R = 9 Ohm
dB/dt = 0.19 T/s
A = 0.025 m^2
induced emf = A * dB/dt
induced emf = 0.025 * 0.19
induced emf = 4.75 *10^-3 V
part B)
induced current = induced emf/R
induced current = 4.75 *10^-3/9 A
induced current = 0.527 mA
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.