During a neighborhood baseball game in a vacant lot, a particularly wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 142-g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 11.7 m/s, shatters the glass as it passes through, and leaves the window at 8.79 m/s with no change of direction.

1.What is the direction of the impulse that the glass imparts to the baseball?

a) The direction of the ball's motion

b) Opposite the direction of the ball's motion

c) Niether of these

2. Calculate the magnitude of this impulse (a positive number). (N*s)

3. The ball is in contact with the glass for 10.3 ms as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number). (N)

Explanation / Answer

1.) Impulse = mass * change in velocity/t

direction = Opposite the direction of the ball's motion

2. Impulse = mass* change in velocity

Impulse = 0.142 ( 11.7 - 8.79 )

J = 0.4132 Ns

3.) J = Favg(time spent)

J = Favg * 10.3*10^-3

Favg = 40.118 N

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