Pre lecture: Collisions x Prob Chapter 7 x W Semi-major C fi https: pitphy 50384

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Pre lecture: Collisions x Prob Chapter 7 x W Semi-major C fi https: pitphy 503841& 57832 E Apps N Netflix NEST a Creighton a FlipltPhysics C Chegg a openstax f Facebook First National Ban P MasteringChem Learning Catalytic O YouTube a Amazon E Etsy wiR Word Reference Pt Dynamic Periodic w WhenTowork 1 2 3 Standard Exercise 7.59 A 0.0750-kg ball is thrown at 24.0 m/s toward a brick wall Standard Exercise 7.60 1) Determine the impulse that the wall imparts to the ball when it hits and rebounds at 24.0 m/s in the opposite direction. The positive direction is toward the wall. (Express your answer to three significant figures) Standard Exercise kg m Submit 7.62 Standard Exercise 7.64 2) Determine the impulse that the wall imparts to the ball when it hits and rebounds at an angle of 45.00. The positive direction is toward the wa (Express your answer to three significant figures) Standard Exercise 7.65 kg Submit Standard Exercise 7.66 3) If the ball thrown in part (b) contacts the wall for 0.0100 s, determine the magnitude and direction of the force that the wall exerts on the ball. The positive direction is toward the wall. (Express your answer to three significant Standard Exercise figures) 7.82 N Submit Interactive Example Bullet and Can T De ENG 9:38 PM 22/2016 Pa I'm Cortana. Ask me anything

Explanation / Answer

Initial Velocity v1 = 24 m/s,

Final Velocity v2= - 24 m/s,

mass m = 0.075 kg,

Impulse J = ?

Impulse is given by

J = mv2 - mv1

J = m(v2 - v1)

J = 0.075*(-24 -24)

J = - 3.6 kg.m/s

where the '-' indicates that the impulse was opposite the original direction of motion.

2)

final momentum at x axis direction = mvcos(45) = - 0.075*24*cos(45) = - 1.27 kg.m/s

impulse at x direction = - 1.27 - 0.075*24 = - 3.07 kg.m/s

final momentum at y axis direction = mvsin(45) = - 0.075*24*sin(45) = - 1.27 kg.m/s

impulse at y direction = - 1.27 - 0 = - 1.27 kg.m/s

so magnitude of impulse = sqrt(3.07^2 + 1.27^2) = 3.32 kg.m/s

c)

The impulse is the product of force and time.

impulse = F*t

Force = 3.32/0.01 = 332 N

direction of force is equal to direction of impulse

theta = arctan(1.27/3.07) = 22.47 degrees

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