Earth\'s magnetic field is about 0.520 G at the magnetic poles, and is pointed v

Question

Earth's magnetic field is about 0.520 G at the magnetic poles, and is pointed vertically downward at the magnetic pole in the northerrn hemisphere. If the magnetic field were due to an electric current circulating in a loop at the radius of the inner iron core of Earth (approximately 1300 km), (a) what would be the magnitude of the current required? X A (b) What direction would this current have? O The same direction as Earth's spin. Opposite the direction of Earth's spin. (c) Explain your answer. This answer has not been graded yet. eBook Submit Answer Save Progress Practice Another Version

Explanation / Answer

1 Gauss = 10^-4 T

magnetic field at the center of circular loop is B =mu_0*i/*2*R

0.52*10^-4 = (4*3.142*10^-7*i/(2*1300*1000)

electric current is i = 107574793.12 A = 1.075*10^8 A

if the direction of current is in direction of spin then the magnetic field is vertically upwards

to get B in the direction of vertially downward the direction of i should be opposite direction of the Earth's spin

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.