Write an expression for the work. W_j, done by the friction force between the ra

Question

Write an expression for the work. W_j, done by the friction force between the ramp and the skateboarder in terms of the variables given in the problem statement. Expression : W_f = ____ Select from the variables below to write your expression. Note that all variables may not be required. cos(theta), sin(theta), alpha, beta, pi, rho, theta, d, g, h_y, m_s, P, t, v_r, W_f The ramp nukes an angle theta with the ground, where theta = 30 degrees. Write an expression foe the magnitude of the friction force, f between the ramp and the skateboarder. Expression : F_f =_____ Select from the variables below to write your expression. Note that all variables may not be required. cos(theta), sin(theta), alpha, beta, pi, rho, theta, d, g, h_y, m_s, P, t, v_r, W_f When the skateboarder reaches the bottom of the ramp, he continues moving the speed v_f onto a flat surface covered with the friction between the grass and the skateboarder brings him to a complete stop after 5.00 m. Calculate the magnitude of the friction F_grass in newtons, between the skateboarder and the grass. Numeric : A numeric value is expected and not an expression. F_grass =

Explanation / Answer

useful power out put will consist of two parts: raising 2350 to a height of 32 m + accelerating 10,000 kg

= 2350 (9.8)( 32)/ 14 + 0.5 x 10000( 4.150^2 / 14 = 52640 + 6151= 58791 Watts apprx

b) cost = 105 watts hour--- cost of energy

energy consuption = 58791 ( 14/ 3600 ) = `228.6316 watts - hour

cost = 105 (  `228.6316) = 24006 . 325 apprx

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