1) At what angle is the first-order maximum for 450.0nm (nm, is nano-meters) wav

Question

1)  At what angle is the first-order maximum for 450.0nm (nm, is nano-meters) wavelength blue light falling on double slits separated by 0.0500 mm (mm, milli-meters)? (report the angle as a positive number in degrees, make sure you calculator is in degrees when doing calculations)

2)

Calculate the angle for the third-order maximum of 580.0nm wavelength yellow light falling on double slits separated by 0.100 mm. (report the angle as a positive number in degrees, be very careful on your sig figs here, make sure you calculator is in degrees when doing calculations).

3) Calculate the wavelength of light that has its third minimum at an angle of 30.0 degrees when falling on double slits separated by 3.00 microns. (answer in nano-meters, make sure you calculator is in degrees when doing calculations)

Calculate the angle for the third-order maximum of 580.0nm wavelength yellow light falling on double slits separated by 0.100 mm. (report the angle as a positive number in degrees, be very careful on your sig figs here, make sure you calculator is in degrees when doing calculations).

Explanation / Answer

here,

1)

wavelength , lamda = 4.5 * 10^-7 m

slit width , d = 0.05 * 10^-3 m

let the angle be theta

for first order, n = 1

d * sin(theta) = lamda

5 * 10^-5 * sin(theta) = 4.5 * 10^-7

theta = 0.52 degree

the angle is 0.52 degree

2)

wavelength , lamda = 5.8 * 10^-7 m

slit width , d = 0.1 * 10^-3 m

let the angle be theta

for third order, n = 3

d * sin(theta) = 3 * lamda

1 * 10^-4 * sin(theta) = 3 * 4.5 * 10^-7

theta = 0.77 degree

the angle is 0.77 degree

3)

theta = 30 degree

d = 3 * 10^-6 m

n = 3

let the wavelength be lamda

d * sin(theta) = n * lamda

3 * 10^-6 * sin(30) = 3 * lamda

lamda = 0.5 * 10^-6 m

lamda = 500 nm

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