Two cars collide at an intersection. Car A , with a mass of 2000 kg , is going f

Question

Two cars collide at an intersection. Car A, with a mass of 2000 kg , is going from west to east, while car B, of mass 1500 kg , is going from north to south at 13.0 m/s . As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65.0 south of east from the point of impact.

Part A

How fast were the enmeshed cars moving just after the collision?

Part B

How fast was car A going just before the collision?

Explanation / Answer

Speed of car A before before collision = v

then velocity of car A = v i

velocity of car B = 13(-j) m/s

Using momentum conservation for collision,

2000 x Vi + 1500 x 13(-j) = (2000 + 1500)vf (cos65i - sin65j)

2000Vi - 19500j = 1267.85vfi - 2718.92Vfj

along J vector:

19500 = 2718.92vf

vf = 7.17 m/s ...........Ans(A)

B) along i vector,

2000 V = 1267.85 vf

V = (1267.85 x 7.17) / 2000 = 4.45 m/s

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