An electron moves with speed 1.0 time sign 10^5 m/s, in the plane of the page as

Question

An electron moves with speed 1.0 time sign 10^5 m/s, in the plane of the page as shown. A 3.00 time sign 10^-5T magnitude field is directed out the page as shown. What is radius and direction of the circle that the electron moves in? 0.019 m, clockwise 0.019 m, counterclockwise 1.9 time sign 10^3 m, clockwise 1.9 time sign 10^3 m, counterclockwise Cannot be determined A long wire carries a current of 500.0. A to the right as shown. A 2.00 m length of carrying 500.0 a of current to the right is located a distance of 1.0 cm below the What is the resulting force on the 2.00 m length of wire? 0.010 N 0.01 N 0.31 N 5.0 N 10 N

Explanation / Answer

F = qVxB

Fe = Fm

qvB = mv^2/r

r = mv/qB = 9.11*10^-31*1*10^5/()1.6*10^-19*3*10^-5)

r = 0.0189 m = 0.019 m

direction will be counter clockwise

Correct answer is option B.

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