A series AC circuit contains a resistor, an inductor of 210 mH, a capacitor of 5

Question

A series AC circuit contains a resistor, an inductor of 210 mH, a capacitor of 5.30 muF, and a generator with deltav_max = 240 V operating at 50.0 Hz. The maximum current in the circuit is 150 mA. (a) Calculate the inductive reactance. Calculate the capacitive reactance. Calculate the impedance. Impedance is the effective resistance as a function of frequency. If you know the maximum current and the maximum voltage, how do you find the impedance? kohm Calculate the resistance in the circuit. The impedance is a function of the resistance and the impedances of the inductor and capacitor, kohm Calculate the phase angle between the current and the generator voltage. The phase angle is a function of the resistance and the reactances of the capacitor and the inductor.

Explanation / Answer

Here

Inductance = 210mh

Capacitance = 5x10-6F

Operating frequency =50Hz

Current = 150mA

Now angular frequency = 2f = 2x3.14x50 = 314rad/s

Impedance (Z) = V/I = 240/0.150 =1600=1.6k

The capacitive reactance is,

                XC= 1/(2fC)

                 =636.94 (~637 )

The inductive reactance is,

Now the resistance R = sqrt ( Xc2 +XL2) = srqt ( 6372+662)

R = 640.41

The phase angle = tan-1( (XC-XL) /(R)) = tan-1(637-66 / 640.41)

= 41.72 (~42O)

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