Two blocks of masses m1 = 1.96 kg and m2 = 4.36 kg are each released from rest a

Question

Two blocks of masses m1 = 1.96 kg and m2 = 4.36 kg are each released from rest at a height of h = 4.90 m on a frictionless track, as shown in the figure below, and undergo an elastic head-on collision.

A. Determine the velocity of the m1 = 1.96 kg block just before the collision.

B. Determine the magnitude of the velocity of the m2 = 4.36 kg block just after the collision.

C. Determine the magnitude of the velocity of the m1 = 1.96 kg block just after the collision.

D. Determine the maximum heights to which m2 rises after collision.

E. Determine the maximum heights to which m1 rises after collision.

Explanation / Answer

a) Potential energy will convert into kinetic energy

=> 0.5*m1*V^2 = m1*g*h

=> v= sqrt(2gH) = sqrt(2*9.8*4.9) = 9.8 m/s Answer

b) Velocity will just interchange

So V2 = 9.8 towards right

c) V1 = 9.8  towards right

d) Since velocity is same both will reach at same height

=> h = 4..9 m

e) h = 4.9 m

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