A particle of charge 21 µC and mass 1.5 10-15 kg moves at a speed of 2240 m/s, a

Question

A particle of charge 21 µC and mass 1.5 10-15 kg moves at a speed of 2240 m/s, and its velocity vector lies in the x—y plane. There is a magnetic field of magnitude 0.90 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x—y plane.

(a) Find the radius of this circle.

(b) Find the period of the motion.

(c) If the particle is moving parallel to +y at t = 0, is the circular motion clockwise or is it counterclockwise as viewed from along the +z axis?

Explanation / Answer

centripetal force = magnetic force

mv^2/r = qvB

r = mv/qB

given :

m = 1.5 x 10^-15 kg

v = 2240 m/s

q = 21 x 10^-6 C

B = 0.90 T

r = 1.78 x 10^-7 m

part b )

T = 2pi*r/v

T = 4.9867 x 10^-10 s

part c )

by right hand rule clock wise

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