The two wires shown in the figure below are separated by d- 10.4 cm and carry cu

Question

The two wires shown in the figure below are separated by d- 10.4 cm and carry currents of I = 5.15 A in opposite directions. (a)Find the magnitude and direction of the net magnetic field at a point midway between the wires. magnitude direction Find the magnitude and direction of the net magnetic field at point Pt, 10.4 cm to the right of the wire on the right, magnitude mu T direction (c) Find the magnitude and direction of the net magnetic field at point P_2,2d = 20.8 cm to the left of the wire on the left. muT

Explanation / Answer

a)
B = miuo*I / (2*pi*r)
r = d/2 = 10.4 /2 = 5.2 cm = 0.052 m

Bdue to right wire,
BR = miuo*I/(2*pi*r)
= (1.2566*10^-6 * 5.15) / (2*pi*0.052)
= 1.98*10^-5 T

Bdue to left wire,
BL = miuo*I/(2*pi*r)
= (1.2566*10^-6 * 5.15) / (2*pi*0.052)
= 1.98*10^-5 T

B due to both wires are into the plane
Bnet = BR+BL
= 1.98*10^-5 T + 1.98*10^-5 T
= 3.96*10^-5 T
Answer:
3.96*10^-5 T
into the page

b)
r1= d = 10.4 cm = 0.104 m
r2 = 2s = 0.104*2 = 0.208 m

Bdue to right wire,
BR = miuo*I/(2*pi*r1)
= (1.2566*10^-6 * 5.15) / (2*pi*0.104)
= 9.9*10^-6 T

Bdue to left wire,
BL = miuo*I/(2*pi*r)
= (1.2566*10^-6 * 5.15) / (2*pi*0.208)
= 4.95*10^-6 T

BR is out og page and BL is into the page
Bnet = BR - BL
= 9.9*10^-6 T - 4.95*10^-6 T
= 4.95*10^-6 T
Answer:
4.95 micro Tesla
out of the page

please solve c.
It is similar to b

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