Required information Read the overview and complete the interactivities that fol
ID: 144521 • Letter: R
Question
Required information Read the overview and complete the interactivities that follow. Cotransduction can be used to map bacteria genes. A small portion of the bacterial chromosome is taken up by a bacteriophage and transferred to a new bacterium upon subsequent infection. The following questions deal with cotransduction Part 7 of 7 Read the report and answer all questions 10 points Results Selected Nonselected Number of colonies Cotransduction frequency gene gene that grew on medium medium + arginine eBook ne arginine 50 met arg 21 0.42 Print Cotransduction frequency equals the number with both traits divided by the total number with the first trait. Rcferences True or False True FalseExplanation / Answer
In the process of Transuction a donor cell transfer its genetic material DNA(Deoxy Ribo Nucleic Acid) to the recipient cell genome by homologus recombination.
The homologus transfer between two or more genes into the recepient genome is termed as Co-transduction. The frequency with which this transfer of gene happens is called Co-transduction frequency. Cotransduction frequency depends on the proximity the genes are located to the donor chromosome. The gene order is determined based on the frequency of cotransduction which plays a vital role in evolution.
The closer the two genes are greater will be the cotransduction frequency. So the cotransduction frequency is inversely proportional to the distance of the two genes.
Cotransduction frequency CF = number with both the traits / total number with the first triat
0.42 = 50 +21 / total number with the first trait
42/100 = 71 / total number with the first trait
total number with the first trait = 71 x 100/42 = 7100 /42
= 1690.48
hence if the met+ trait totals to 1690.48 the cotransduction frquency will 0.42. So the given cotransduction frequency will be true.
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