Two circuits contain an emf produced by a moving metal rod, like that shown in t
ID: 1445341 • Letter: T
Question
Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 46 , and that in circuit 2 is 92 . Determine (a) the ratio 1/2 of the emfs and (b) the ratio I1/I2 of the currents in the circuits. (c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?
Explanation / Answer
a) Setup is same for both circuit except bulb.
and induced emf, e = B L v = same (no R in there)
so e1/e2 = 1
b) I = e/R
I1/I2 = (e /46) / (e/92) =2
c) when speed is twince in 1
then e1 = 2BLv and e2= BLv
e1= 2e2
P = e^2 / R
P1/P2 = ( e1^2 / 46 ) / (e2^2 / 92) = (4 e2^2 /46) / (e2^2 / 92)
= 8
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.