This question has 4 parts, and 3 figures, each screenshot shows a different figu
ID: 1445554 • Letter: T
Question
This question has 4 parts, and 3 figures, each screenshot shows a different figure on the left.
Prelecture Video: Faraday's Law Part A Click Play to watch the video. Answer the ungraded questions in the video and the graded follow-up questions at right. A conducting rod is being dragged along conducting rails, as shown in (Figure 1). The magnetic field is directed out of the screen. In what direction does the induced current flow through the light bulb? There is no induced current The induced current flows through the bulb from the left to the right. PEARSON ALWAYS LEARN Faraday's Law Figure 1 The induced current flows through the bulb from the right to the left 013 Submit My Answers Give Up Part B A circular loop of conducting wire is moving through a uniform magnetic field, as shown in (Figure 2). Is a non-zero emf induced in the loop? Yes O No Submit My Answers Give Up Part C A wire loop is rotating at a constant angular frequency within a uniform magnetic field B. The orientation of the magnetic field is shown at three moments in time below. E T Rank the orientations from lowest to highest magnitude of the instantaneous induced emf.Explanation / Answer
here,
Question 1:
part 1:
From Right Hand rule, Curl your fingure's in direction of magnatic field, thumb gives direction of magnatic field.
The current will flow from left to right i,e clockwise direction.
Part 2:
yes EMF will since,
Induced EMF is rate of change of magnatic flux multiplied by no of turns of coil.
Part 3:
Induced EMF given as:
EMF = n*B*A*CosA
condition 1, A = 90 plate is perpendicular to horizontal,
EMF = n*B*A*Cos90
EMF = 0
condition 2, A = 45,
EMF = n*B*A*Cos45
EMF = 0.707*n*B*A
condition 1, A = 0
EMF = n*B*A*Cos0
EMF = n*B*A
Con 3 > Con 2 > Con 1
Part 4:
Part b is correct Answer, since outside field is zero
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