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(a) immediately after the switch is closed (after being open a long time)... ...

ID: 1445764 • Letter: #

Question

(a) immediately after the switch is closed (after being open a long time)...
...the current through the inductor
IL = _________ mA

...the current through R2
I2 = _________mA


(b) a long time after the switch has been closed...
...the current through the inductor
IL = _________ mA

...the current through R2
I2 = _________mA

(c) immediately after the switch is open (after being closed a long time)...
...the current through the inductor
IL = __________mA

...the current through R2
I2 = __________mA

(d) a time 1.144e-03 s after the switch is open....
...the current through the inductor
IL = __________mA

...the current through R2
I2 = __________mA

Explanation / Answer

a) Just after switch is closed.

current doesn't change in indcutor instantly.

hence current through inductor = 0

IL = 0

current through R2, I2 = 10 / (210 + 300) = 0.0196 A   = 19.6 mA

b) after long time.

no current will flow through R2, all the current will go through inductor.

iL = V/R1 = 10 / 210 = 0.0476 A = 47.6 mA

I2 = 0

c) current will not change instantly through inductor.

so IL = 47.6 mA


I2 = 47.6 mA

d) as time elapses, current through inductor start decreasing.

IL = I [ e^(-tR2/L) ]

at t = 1.144 x 10^-3 s

IL = 47.6 [ e^(- 1.144 x 10^-3 x 300 / 0.264)] = 12.97 mA

I2 = 12.97 mA