A 0.0950-kg ball is thrown at 28.0 m/s toward a brick wall. Determine the impuls

Question

A 0.0950-kg ball is thrown at 28.0 m/s toward a brick wall. Determine the impulse that the wall imparts to the ball when it hits and rebounds at 28.0 m/s in the opposite direction. The positive direction is toward the wall. (Express your answer to three significant figures). Determine the impulse that the wall imparts to the ball when it hits and rebounds at an angle of 45.0 degree. The positive direction is toward the wall. (Express your answer to three significant figures). If the ball thrown in part (b) contacts the wall for 0.0100 s, determine the magnitude and direction of the force that the wall exerts on the ball. The positive direction is toward the wall. (Express your answer to three significant figures).

Explanation / Answer

part a )

J = m(vf-vi )

here vf = -28 m/s

vi = 28 m/s

m = 0.0950 kg

J = 0.0950(-28 -28)

J = 5.32 kg-m/s

part b )

ball rebouns at 45 angle

initiallt there no motion in y direction

in x direction

Jx = m(vf - vi)

vf = -28cos45

vi = 28

Jx = -4.54

in y direction

vi = 0

vy = 28sin45

Jy = 1.88

J = sqrt(Jx^2+Jy^2)

J = 4.91 kg-m/s

part c )

Favg = J/dt

Favg = 491 N

direction = theta = tan^-1(Jy/Jx)

theta = 157.5 degree

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