Your cat “Ms.” (mass 8.00 kg ) is trying to make it to the top of a frictionless

Question

Your cat “Ms.” (mass 8.00 kg ) is trying to make it to the top of a frictionless ramp 2.00 m long and inclined 19.0 above the horizontal. Since the poor cat can’t get any traction on the ramp, you push her up the entire length of the ramp by exerting a constant 55.0 N force parallel to the ramp.

Now, draw the most convenient coordinate system for this problem. The orientation of the vectors should be accurate.

Ms. is moving at 2.00 m/s at the bottom of the ramp, what is her speed when she reaches the top of the incline?

Explanation / Answer

Fres = ma

along the ramp

Fres = 55 - 8g sin19° = 8a

=> a = 3.684m/s²

v² = u² + 2as

=> v² = 2² + 2x2.(3.684)

=> v² = 4 + 9.9044

v =4.328 m/s

The speed when she reaches the top of the incline is 4.328 m/s

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