The basement floor of a certain house is 12 feet below the surface of the ground

Question

The basement floor of a certain house is 12 feet below the surface of the ground. There is no provision for drainage away from the foundation, so that during extended rainy periods the soil in contact with the house become saturated. This is effectively a 12 foot depth of water at the point where the wall Joins the floor. Calculate the water pressure in lb/in^2 which acts to make the basement leak. A stone is found a mass of 60 kg and an apparent mass of 38 Kg when it is submerged in water. Find its volume and density. A water pressure of 20 cm H_20 is applied at one end of a tube of length 50 cm. When the other end of the tube is opened, the flow rate is 200 cm^3/rain. Assuming Laminar Flow calculate the flow rate if the following changes are made individually with the other parameters set at their original values: The pressure was increased to 40 cm H_20. The length of the tube was increase

Explanation / Answer

A) As depth increase pressure increases.

According to bernoulli' equation,

P + rho*g*h + rho*v^2 / 2 = constant

at top = at bottom

Patm +(1000 x9.8 x (0.3048 x 12) m ) + 0 = Pwater + 0 + 0

101325 Pa + 35844.48 = Pwater +

Pwater = 137169.48 Pa ...........Ans

( and pressure difference will be 35844.48 Pa)

b) suppose volume of stone is V and density is rho.

Apparent mass = actual mass - mass of displaced water

mass = volume x density

density of water is 1000 kg / m^3 .

38 = 60- (1000 * V)

V= 0.022 m^3 ........An

and V* rho = 60 kg

0.022 x rho = 60

rho = 2727.27 kg / m^3

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