could you answer i. and ii.? Two blocks are on a frictionless, level track. Bloc

Question

could you answer i. and ii.? Two blocks are on a frictionless, level track. Block B has more mass than block A. Initially, block B is moving toward block A, which is at rest. After the collision, the blocks stick together. At the instant of collision, how does the normal force on block A by block B compare with the net force on block B by block A? Discuss both magnitude and direction. For any given time interval Delta t during the collision, how does the impulse on block A compare with the impulse on block B? Discuss both magnitude and direction.

Explanation / Answer

mass of B = M
mass of A = m
velocity of B = u
velocity of both after collision = v

1. before collision, momentum of B = Mu -- 1
after collision, momentum of both = Mv + mv = Mu [momentum conservation]
so v = Mu/[M+m] -- 2

change in momentum of A = mv - m*0 = mv = mMu/[M+m] = impulse = F1dT

similiarly, change in momentum of B, Mv - Mu = M(Mu/[M+m] - u) = Mu(M-M+m)/(M+m) = Mmu/[M+m] = impulse = F2dT
since, dT is same for both, F1 = F2
where f1 and F2 are reaction forces at the time of collision, anf dT is time taken for teh momentum to shift

Force due to A on B is towards B, and due to B on A is towards A

2. Impulse is same and is given by FdT [ as discussed in previous question]

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