We have two objects, both made from brass. One is a solid cube and the other is

Question

We have two objects, both made from brass. One is a solid cube and the other is a solid constructed of 12 brass rods (the rods from the edges of a cube). Each cube has dimensions of 0.10 m x 0.10 m x0.10 m. Originally, each cube is at 20 C but their temperatures are raised to 180 C.
a) Calculate the new volume of the solid cube of brass.

I did part a and got it correct. My final volume was 1009.12 m.

b) Calculate the new volume of the empty, faceless cube of brass.
This is the part I need help with, please. I know we would calculate the change in length using (delta)L = alpha Lo(delta)T. I used this equation and got (19e-6)(0,10)(180-20) = 0.000304m. I believe I should then find the change in the volume. Would that just be cubing that number? Thank you for any help you can provide me.

Explanation / Answer

New Length is (19e-6)(0,10)(180-20) = 0.000304m

New Volume = (0.000304m)^3 = 2.8*10^-11 m^3

It would be Cubing the new length.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.