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1)A transformer is to be used to provide power for a computer drive. The number

ID: 1448512 • Letter: 1

Question

1)A transformer is to be used to provide power for a computer drive. The number of turns in the primary is 1000, and it delivers a secondary current of 600 milliamperes (mA) at a secondary voltage of 8.0 V for the drive. A voltage of 400 volts is applied across the primary. What kind of transformer is this? (Step-down, AC, Load, Regulated, or Step-up)

2)Determine the number of turns in the secondary of the transformer in Question 1.

3)Determine the primary current in milliamps of the transformer in Question 1.

4)A transformer is said to be ideal if the power developed across the primary equals the power developed across the secondary. Assuming the transformer used in Question 1 is ideal, find the power (P=IV) in watts developed across either the primary or secondary.

Please explain and show all your work! Thank you.

Explanation / Answer

1. Step Down

2.number of turns = v1/v2 = n1/n2 so, n2 = n1*v2/v1 = 1000*8/400 = 20

3.Primary Current = 600*20 = 12000 milli Amperes

4. P = iV = 600*10^-3*8 = 2.4 W