GPS (Global Positioning System) satellites orbit at an altitude of 3.0×10 7 m .
ID: 1448681 • Letter: G
Question
GPS (Global Positioning System) satellites orbit at an altitude of 3.0×107 m .
A- Find the orbital period.
T=_________h
B - Find the orbital speed of such a satellite.
v=_______m/s
2- IP At a certain distance from the center of the Earth, a 5.0-kg object has a weight of 3.5 N
A- Find this distance.
r=_________m
B- If the object is released at this location and allowed to fall toward the Earth, what is its initial acceleration?
a=_______m/s2
C- If the object is now moved twice as far from the Earth, by what factor does its weight change?
w1/w2= _______
Explanation / Answer
b)
Vo= sqrt [ (G*m)/(R+h) ]
Vo= sqrt [ (6.67x10^-11 * 6x10^24)/ (6400x10^3 + 3x10^7)
Vo= 3.316 x10^3 m/s
a)
T= 2pi (R+h) / Vo
T= 2pi (6400x10^3 + 3x10^7) / 3.316x10^3
T= 68.97 x10^3 s
------------------------------------
a-----equation is r=sqrt(G(Mass of earth)(Mass of object))/weight) you could do the calculations.
b-----F=ma so ==> a=F/M=3.5/5.0
c------(c)It's an inverse square law, so 2.0 times further would be ( ½ )^2 = 1/4=0.25
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