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ID: 1449000 • Letter: S
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ON N INCLINED PLAN€, THE COEFFICIENT OF FRICTION IS (h. 0.2). Ax= 0.2). THE INCLINATION'S 450, THE DISTANCE THE MELI NAnbKIS MASS FROM POINT A TO POTNT B ALOKD THE PATH #8, AND THE FINAL VELOCITy 150 FIND THE MASS OF THE th. BoDy . SSUME IT, STARTED FROM REST. INSTRUCTION: DRAW LLThHE FORCE VECTORS PROPERLY O POINTS NUS : FINpour How MUCH WORK DONE IS PERFORMED By 5POINTSExplanation / Answer
THe length from A to C will be
AC = BC tan (45) =4 m
AB = BC sec 45 = 5.65 m
The forces acting on the mass will be . Weight vertically down, friction up the incline at 45 degree from horizontal and normal force normal to the plane .
Hence we can write the net force equation as
mg sin (45 ) - uk N = ma
N = mg cos (45)
Using1 work energy energy theorem
mgh - uk N AB = 1/2mv^2 - (Initial kinetic energy)
Note = THe value of Vf is more than the maximum value for Vf if starting from rest. Hence you need to have initial kinetic energy. In this case the max speed can be sqrt (2*4*9.8) = 8.85 m/s without friction) . Once you know the intial kinetic energy put it in above equation to get the mass.
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