On February 23, 1987 astronomers noticed that a relatively faint star in the Tar
ID: 1449902 • Letter: O
Question
On February 23, 1987 astronomers noticed that a relatively faint star in the Tarantula Nebula in the Large Magellanic Cloud suddenly became so bright that it could be seen with the naked eye. Astronomers suspected that the star exploded as a supernova. Late-stage stars eject material that forms a ring before they explode as supernovas. The ring is at first invisible. However, following the explosion the light from the supernova reaches the ring. Astronomers observed the ring exactly one year after the phenomenon itself occurred. Use geometry and the speed of light to estimate the distance to the supernova. The angular size of the ring is 0.81 arcseconds. Calulate the distance.
Explanation / Answer
Radius of the ring R = distance =speed of light x time required
R=3*10^8*365*24*60*60
R=9.461*10^12 km
Angular size (a) = 0.81
sec theta = 0.81/3600 degrees
theta =0.000225 degrees
Distance (d) = time / tan (a)
= 1/tan(0.000225) = 254647.91light years
D= 250000 light years= 25*10^4 light years
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