Two containers, X and Y, both contain nitrogen gas at a temperature of 30° C and

Question

Two containers, X and Y, both contain nitrogen gas at a temperature of 30° C and a pressure of 1 atm. The initial volume of each of the containers is V30 = 0.5 liters. The only difference between the two containers is that while container X has a piston that is sealed and cannot move, the gas in container Y is allowed to expand against the surrounding atmosphere.QX is the amount of heat required to raise the temperature of the gas in container X by 10° C, and QY is the amount of heat required to raise the temperature of the gas in container Y by 10° C.What is the difference between QX and QY?Use 0°C = 273.15 KQX - QY =

Explanation / Answer

P = 101325 Pa
V = 5*10^-4 m^3

Both containers have the same number of particles of identical gas, and the same change in temperature, So to raise the temperature by the same amount, we must add the same amount of internal energy to each X and Y.

QX = QV = U

QX - QY = U - (U + W) = -W
Where, Work done, W = p30 (V40 - V30)
Where, Work done, W = nRT = pV30 T / T30
W = (101325*5*10^-4*10)/(30 + 273.15)
W = -1.67 J

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.