This experiment includes a rotating disk attached by a cable over a pulley to a

Question

This experiment includes a rotating disk attached by a cable over a pulley to a hanging mass (see Figure 2), which provides a torque on the disk. The mass hanger only moves vertically, and the disk just spins about its center, so there are only two relevant equations from Newton's second law. These two equations are connected through T, the tension in the string, and the relation between a and a. Because the string connects to the hanger and encircles the disk, the hanger's displacement is related to the disk's angular displacement by Delta x = r Delta theta. According to the definition of velocity and acceleration, we also have v = r omega and a = r alpha. Finally, rotating bodies have kinetic energy, which is of the same form as the kinetic energy of translational motion and is given by K_rot = 1/2 I omega^2 The rotational kinetic energy is considered as a mechanical energy and should be incorporated into the energy conservation law. Are those below proper units of the moment of inertia? kg^2 Times m; kg times m^2; Newton Times m; Newton times m Times s^2; 5. Joule/s. Considering the top-down view of the disc in Figure 2, are the statements below correct? The torque is toward the page The torque is outward from the page. The torque is perpendicular to the disk. The torque lies on the plane of the disk. The torque is parallel to the tension T. Considering the setup in Figure 2, when the hanger is released to fall, are the statements below correct? The hanger falls at a constant acceleration. The hanger's gravitational potential energy converts to the hanger's kinetic energy and the disk's rotational kinetic energy. The hanger's kinetic energy is always equal to the disk's rotational kinetic energy. The larger the disk's moment of inertia is, the larger the disk's angular acceleration is. The larger the hanger's mass is, the larger the disk's angular acceleration is.

Explanation / Answer

1. Kg m2

2. Statements 1, 3 are correct , Since Torque is perpendicular to Tension and radius.

3. Statements 1, 2 and 5 are correct

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