question3 An electric power line carries a strong current of 1.75 times 10^-3 A
ID: 1450643 • Letter: Q
Question
question3
An electric power line carries a strong current of 1.75 times 10^-3 A in the lovely city of Auchorage, Alaska. The line is parallel to the ground and heading to the North (also the direction of the electric current), but since the Earth is a sphere it means that the Earth's magnetic field of 55 mu T is oriented at an angle of 61 degree relative to the wire (see figure). Determine the force on a 30.0 m segment of the power line, and use the right-hand rule to determine its direction. You had so much fun making a capacitor that you decide to make an electric motor (more motion equals more fun!). You have copper wire (resistivity, rho = 1.70 times 10^-8 ohm) with a cross-sectional area of 2.00 times 10^-7 m^2, and using 1.00 m of this wire you make a rectangular coil with sides having lengths of 3.00 cm and 2.00 cm. You will be using a neodymium magnet, so you can immerse your coil in a 0.60 T magnetic field. You will power the motor with a standard D-cell battery, so the potential difference is 1.50 V. Determine the maximum torque on your electric motor. (There are a lot of little steps in this problem; how much area is one coil? how many coils can you make? what is the resistance of your wire? etc.) Jupiter has a strong magnetic field, and volcanism on its moon Io is constantly injecting high velocity sulfur dioxide into the space surrounding Jupiter. This sulfur dioxide gets dissociated into other ions, including SO+ which has a mass of 7.97 times 10^-26 kg and a charge equivalent to a single fundamental unit of charge. If the radius of the circular path of an SO+ ion having a velocity of 7.0 times 10^4 m/s perpendicular to the magnetic field is 39.0 m, what is the magnetic field strength at this location?Explanation / Answer
#3:
magnetic force of charged particle palced in uniorm magnteic field is given by
F = iLB sin theta
where i is current
L is length
B = magnetic field
theta is the angle betweeen L and B
so here we apply
so
magnetic force F = iL B sin theta
F = 1.75 e 3 * 30 * 55 e-6 * sin 61
F = 2.52 N
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