A block of mass m it pushed against a spring with constant k. The right end of t

Question

A block of mass m it pushed against a spring with constant k. The right end of the spring is initially compressed towards the left by a distance x from its equilibrium position x = 0 and then released from rest. The coefficient of kinetic friction between the block and the table is mu_k The speed of the block when its left side is at x = 0 is Consider a pendulum of length l and mass m that is released from rest at an angle theta_t. The maximum angular and centripetal accelerations are at the angles and respectively An electric clock is hanging or. a vertical wall. The hands of the clock arc moving in the clockwise direction Its battery is losing power and the clock is slowing down. What is the direction of the angular acceleration vector of the minute hand?

Explanation / Answer

kinetic energy of the block=potential energy at x distance+ energy loss due to friction

(1/2)*m*v^2=(1/2)*k*x^2+umgx

v=sqrt (kx^2/m + 2ugx)

44) angular speed must be maximum at mean point i.e. at thiita=0

force=-kx

centripita acceleration must be maximum at thita0

45) acceleration will be along anti clockwise

angular acceleration must be such that the cross product of angular acceleration and radius is along acceleration.

It will be out from the wall.

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