The bulbs in the circuit shown are identical. Switch S initially closed. Rank th
ID: 1451515 • Letter: T
Question
Explanation / Answer
a) when switch S is closed Current through A and E would be same and maximum. since P=I*I/R ans R is same for all byulbs. So ! and E would be brightest . Now Current through A would be divided across D anf BC. Since equivalent resistance of Bc is more than D so more current would pass through D so d will come next followed by B and c .
b) answer explained in a)
c)when switch S is opened B anc C will not come to play and only D would be there. The Eqv resistance of BCD would be lesser than D . So now less current would pass through A and brightness will decrease.
d) voltage drop would decrease as less current would pass through.
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